How to use the LineGeometry function from three

Find comprehensive JavaScript three.LineGeometry code examples handpicked from public code repositorys.

three.LineGeometry is a class in the Three.js library that represents the geometry of a line object.

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for (let i = 0, l = points.length * divisions; i < l; i++) {
  let point = spline.getPoint(i / l)
  positions.push(point.x, point.y, point.z)
  colors.push(color.r, color.g, color.b)
}
let geometry = new THREE.LineGeometry()
geometry.setPositions(positions)
geometry.setColors(colors)

return geometry
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  THREE.LineSegments2.call( this );


  this.type = 'Line2';


  this.geometry = geometry !== undefined ? geometry : new THREE.LineGeometry();
  this.material = material !== undefined ? material : new THREE.LineMaterial( { color: Math.random() * 0xffffff } );


};

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How does three.LineGeometry work?

Sure! three.LineGeometry is a class in the Three.js library that represents the geometry of a line object. To create a three.LineGeometry object, you need to specify an array of Vector3 points that define the path of the line. You can also specify the width of the line and other options. Here's an example of how to create a three.LineGeometry object: javascript Copy code {{{{{{{ const geometry = new THREE.LineGeometry(); const points = [ new THREE.Vector3(-10, 0, 0), new THREE.Vector3(0, 10, 0), new THREE.Vector3(10, 0, 0), ]; geometry.setPositions(points); const material = new THREE.LineBasicMaterial({ color: 0x00ff00 }); const line = new THREE.Line(geometry, material); In this example, we first create a new three.LineGeometry object with the new THREE.LineGeometry() constructor. We then define an array of Vector3 points that define the path of the line. Each Vector3 object specifies a 3D coordinate in space. We call the setPositions method of the geometry object to set the positions of the line based on the points array. We then create a THREE.LineBasicMaterial object with a green color. Finally, we create a THREE.Line object by passing in the geometry and material objects as arguments. This creates a line object with a green color that follows the path defined by the points array. This code demonstrates how to use the three.LineGeometry class to define the geometry of a line object.

Ai Example

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const geometry = new THREE.LineGeometry();

const points = [
  new THREE.Vector3(-10, 0, 0),
  new THREE.Vector3(0, 10, 0),
  new THREE.Vector3(10, 0, 0),
];
geometry.setPositions(points);

const material = new THREE.LineBasicMaterial({ color: 0x00ff00 });

const line = new THREE.Line(geometry, material);

scene.add(line);

In this example, we first create a new three.LineGeometry object with the new THREE.LineGeometry() constructor. We then define an array of Vector3 points that define the path of the line. Each Vector3 object specifies a 3D coordinate in space. We call the setPositions method of the geometry object to set the positions of the line based on the points array. We then create a THREE.LineBasicMaterial object with a green color. Finally, we create a THREE.Line object by passing in the geometry and material objects as arguments. This creates a line object with a green color that follows the path defined by the points array. We add the line object to the scene object, which is a container that holds all the objects to be rendered. This code demonstrates how to use the three.LineGeometry class to create a line object in Three.js.

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