How to use the groupWith function from ramda
Find comprehensive JavaScript ramda.groupWith code examples handpicked from public code repositorys.
2174 2175 2176 2177 2178 2179 2180 2181 2182 2183* treated as a list of characters. * @return {List} A list that contains sublists of equal elements, * whose concatenations are equal to the original list. * @example * * R.groupWith(R.equals, [0, 1, 1, 2, 3, 5, 8, 13, 21]) * //=> [[0], [1, 1], [2], [3], [5], [8], [13], [21]] * * R.groupWith((a, b) => a % 2 === b % 2, [0, 1, 1, 2, 3, 5, 8, 13, 21]) * //=> [[0], [1, 1], [2], [3, 5], [8], [13, 21]]
0
0
0+ 53 other calls in file
3918 3919 3920 3921 3922 3923 3924 3925 3926 3927* @example * * R.groupWith(R.equals, [0, 1, 1, 2, 3, 5, 8, 13, 21]) * //=> [[0], [1, 1], [2], [3], [5], [8], [13], [21]] * * R.groupWith((a, b) => a + 1 === b, [0, 1, 1, 2, 3, 5, 8, 13, 21]) * //=> [[0, 1], [1, 2, 3], [5], [8], [13], [21]] * * R.groupWith((a, b) => a % 2 === b % 2, [0, 1, 1, 2, 3, 5, 8, 13, 21]) * //=> [[0], [1, 1], [2], [3, 5], [8], [13, 21]]
002+ 15 other calls in file
GitHub: jcla1/AdventOfCode
12 13 14 15 16 17 18 19 20 21 22 23R.filter(R.compose(R.not, R.equals(''))), R.split(' '))); const boards = R.compose( R.map(R.compose(parseBoard, R.dropLast(1))), R.groupWith(R.compose(R.not, R.equals(''))), R.drop(2))(input); const markNumber = (n) => R.map( R.map(R.ifElse(R.equals(n), R.always(-1), R.identity)));
000
ramda.clone is the most popular function in ramda (30311 examples)