How to use the unapply function from ramda
Find comprehensive JavaScript ramda.unapply code examples handpicked from public code repositorys.
GitHub: raine/flyd-keyboard
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var always = _require2.always; var merge = _require2.merge; var props = _require2.props; var apply = _require2.apply; var identity = _require2.identity; var unapply = _require2.unapply; var zipObj = _require2.zipObj; var setPos = curry(function (elem, left, top) { elem.style.left = left + 'px';
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R.fromPairs, R.map(([k, _]) => [k, R.lensProp(k)]), R.toPairs )(defaults) const mergeString = R.unapply(R.compose( R.defaultTo(''), R.head(), R.reject(isUseless), R.reverse,
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* @param {Function} fn * @return {Function} * @see R.apply * @example * * R.unapply(JSON.stringify)(1, 2, 3); //=> '[1,2,3]' */ var unapply = _curry1(function unapply(fn) { return function () { return fn(_slice(arguments));
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GitHub: jcla1/AdventOfCode
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const possibleSeqs = R.map( R.compose(R.sum, R.unnest), R.xprod(R.xprod([1, 2, 3], [1, 2, 3]), [1, 2, 3])); const quantumGame = R.memoizeWith( R.unapply(R.toString), ([p1, p2], [p1Score, p2Score]) => { p1 %= 10; p2 %= 10; // Only need to check on p2, since he's always going to be the last
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* @return {Function} * @see R.apply * @example * * R.unapply(JSON.stringify)(1, 2, 3); //=> '[1,2,3]' * @symb R.unapply(f)(a, b) = f([a, b]) */ var unapply =
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ramda.clone is the most popular function in ramda (30311 examples)