How to use the isLogicalExpression function from @babel/types
Find comprehensive JavaScript @babel/types.isLogicalExpression code examples handpicked from public code repositorys.
@babel/types.isLogicalExpression is a function provided by the Babel library that checks whether a given abstract syntax tree (AST) node represents a logical expression in JavaScript.
GitHub: yandex/reselector
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if ( t.isCallExpression(parent) || t.isConditionalExpression(parent) || t.isSequenceExpression(parent) || t.isLogicalExpression(parent) ) { return isReturned(p.parentPath) }
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GitHub: menhal/anu
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}, isLoopMap(astPath: any) { if ( t.isJSXExpressionContainer(astPath.parentPath) || t.isConditionalExpression(astPath.parentPath) || t.isLogicalExpression(astPath.parentPath) ) { var callee = astPath.node.callee; return callee.type == 'MemberExpression' && callee.property.name === 'map'; }
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How does @babel/types.isLogicalExpression work?
@babel/types.isLogicalExpression is a function provided by the Babel library that takes in an AST node object and checks whether it represents a logical expression in JavaScript. To determine whether the node is a logical expression, the function checks the node's type property to ensure it is set to 'LogicalExpression', and checks its operator property to ensure it is set to one of the valid logical operators ('&&', '||', or '??'). If both checks pass, the function returns true, indicating that the node represents a logical expression. Otherwise, it returns false. This function can be useful when working with AST nodes in Babel plugins or other code transformation tools, allowing you to easily determine whether a given node represents a logical expression and take appropriate action based on that information.
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function logicalExpressionHandle (ast) { traverse(ast, { noScope: true, LogicalExpression (path) { let parentPath = path.parentPath if (t.isIfStatement(parentPath) || t.isLogicalExpression(parentPath)) { let left = path.get("left") let right = path.get("right") if (t.isBinaryExpression(left) && t.isBinaryExpression(right)) {
GitHub: suchipi/tofu
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return; } } if ( (t.isBinaryExpression(node) || t.isLogicalExpression(node)) && key.length == 1 ) { let newOperator = key; if (key == '=') {
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Ai Example
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const t = require("@babel/types"); const myNode = t.logicalExpression("||", t.identifier("x"), t.identifier("y")); console.log(t.isLogicalExpression(myNode)); // true console.log(t.isLogicalExpression(t.identifier("z"))); // false
In this example, we use @babel/types to create an AST node object representing a logical OR expression with two identifier operands, 'x' and 'y'. We then use @babel/types.isLogicalExpression to check whether this node represents a logical expression, which returns true since it is a valid logical OR expression. We also use @babel/types.isLogicalExpression to check whether a different node representing an identifier, 'z', represents a logical expression, which returns false since it is not a valid logical expression.
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node: await getMemberProperty({ node: node, ast, cwd }), ast, cwd, }); case types.isLogicalExpression(node): return await createDescriptor({ node: node.right, ast, cwd }); } throw `Cannot resolve arguments for ${node.type}`;
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// No handling for ^^ right now } else if ( t.isUnaryExpression(path.node.init) ){ // No handling for ^^ right now } else if ( t.isConditionalExpression(path.node.init) ){ // No handling for ^^ right now } else if ( t.isLogicalExpression(path.node.init) ){ // No handling for ^^ right now } else if ( t.isObjectExpression(path.node.init) ) { // No handling for ^^ right now - i think this is fine generally actually - if objects // are being built up, leaving this will be clearer
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return t.isLogicalExpression(parent, { operator: "??" }); case "??": return t.isLogicalExpression(parent) && parent.operator !== "??"; } } function Identifier(node, parent, printStack) {
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@babel/types.identifier is the most popular function in @babel/types (20936 examples)